720x^2+720x-270=0

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Solution for 720x^2+720x-270=0 equation:



720x^2+720x-270=0
a = 720; b = 720; c = -270;
Δ = b2-4ac
Δ = 7202-4·720·(-270)
Δ = 1296000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1296000}=\sqrt{129600*10}=\sqrt{129600}*\sqrt{10}=360\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(720)-360\sqrt{10}}{2*720}=\frac{-720-360\sqrt{10}}{1440} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(720)+360\sqrt{10}}{2*720}=\frac{-720+360\sqrt{10}}{1440} $

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